Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 3 - Determinants - 3.1 The Determination of a Matrix - 3.1 Exercises: 12

Answer

$\lambda^2-6\lambda+8$

Work Step by Step

$\left| \begin{array}{cc} \lambda-2 & 0 \\ 4 & \lambda-4 \end{array} \right|=ad-bc$ $=(\lambda-2)\times (\lambda-4)-0\times4$ $=\lambda^2-4\lambda-2\lambda+8$ $=\lambda^2-6\lambda+8$
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