Answer
$\lambda^2-4\lambda-4$
Work Step by Step
$\left| \begin{array}{cc}
\lambda-3 & 2 \\
4 & \lambda-1 \end{array}
\right|=ad-bc$
$=(\lambda-3)\times (\lambda-1)-2\times4$
$=\lambda^2-\lambda-3\lambda+4-8$
$=\lambda^2-4\lambda-4$
Elementary Linear Algebra 7th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
1-13311-087-8
ISBN 13:
978-1-13311-087-3
Chapter 3 - Determinants - 3.1 The Determination of a Matrix - 3.1 Exercises - Page 110: 11
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