Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 2 - Matrices - 2.1 Operations with Matrices - 2.1 Exercises - Page 50: 79

Answer

$BA=\left[ {\begin{array}{*{20}{c}} {\$ 1037.5}&{\$ 1400}&{\$ 1012.5} \end{array}} \right]$ Each entry of the matrix represents the total profit from the corresponding outlets.

Work Step by Step

We have: $B= \left[ {\begin{array}{*{20}{c}} \$3.5&\$6\\ \end{array}} \right]$ and $A= \left[ {\begin{array}{*{20}{c}} 125&100&75\\ 100&175&125 \end{array}} \right]$ Then $\begin{array}{l} BA = \left[ {\begin{array}{*{20}{c}} {\$ 3.5}&{\$ 6} \end{array}} \right].\left[ {\begin{array}{*{20}{c}} {125}&{100}&{75}\\ {100}&{175}&{125} \end{array}} \right]\\ = \left[ {\begin{array}{*{20}{c}} {\$ (3.5 \times 125 + 6 \times 100)}&{\$ (3.5 \times 100 + 6 \times 175)}&{\$ (3.5 \times 75 + 6 \times 125)} \end{array}} \right]\\ = \left[ {\begin{array}{*{20}{c}} {\$ 1037.5}&{\$ 1400}&{\$ 1012.5} \end{array}} \right] \end{array}$ Each entry of the matrix represents the total profit from the corresponding outlets.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.