Answer
\begin{align*}
\operatorname{Tr}(AB)&=\sum_{i=1}^n\left(\sum_{k=1}^na_{ik}b_{ki}\right)\\
&=\sum_{i=1}^n\left(\sum_{k=1}^nb_{ik}a_{ki}\right)\\
&=\operatorname{Tr}(BA).
\end{align*}
Work Step by Step
\begin{align*}
\operatorname{Tr}(AB)&=\sum_{i=1}^n\left(\sum_{k=1}^na_{ik}b_{ki}\right)\\
&=\sum_{i=1}^n\left(\sum_{k=1}^nb_{ik}a_{ki}\right)\\
&=\operatorname{Tr}(BA).
\end{align*}