## Elementary Linear Algebra 7th Edition

Published by Cengage Learning

# Chapter 1 - Systems of Linear Equations - Review Exercises: 8

#### Answer

$x$ = -$\frac{2}{3}s$ + $\frac{4}{3}t$

#### Work Step by Step

3$x_{1}$ + 2$x_{2}$ - 4$x_{3}$ = 0 3$x_{1}$ = -2$x_{2}$ + 4$x_{3}$ $x_1$ = -$\frac{2}{3}x_{2}$ + $\frac{4}{3}x_3$ Now add parameters for $x_1$, $x_2$, and $x_3$. So, $x_1$ = $x$ ; $x_2$ = $s$ ; $x_3$ = $t$ $x$ = -$\frac{2}{3}s$ + $\frac{4}{3}t$

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