Elementary Linear Algebra 7th Edition

Published by Cengage Learning
ISBN 10: 1-13311-087-8
ISBN 13: 978-1-13311-087-3

Chapter 1 - Systems of Linear Equations - Review Exercises: 7

Answer

$x$ = $\frac{1}{2}$s -$\frac{3}{2}$t -$\frac{1}{4}$

Work Step by Step

-4$x$ + 2$y$ - 6$z$ = 1 4$x$ = 2$y$ - 6$z$ - 1 $x$ = $\frac{1}{2}$$y$ - $\frac{3}{2}$$z$ - $\frac{1}{4}$ Now add parameters for $y$ and $z$. So, $y$ = $s$, and $z$ = $t$. $x$ = $\frac{1}{2}$s -$\frac{3}{2}$t -$\frac{1}{4}$
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