Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 9 - Inequalities and Problem Solving - Review Exercises: Chapter 9 - Page 623: 40

Answer

no solution

Work Step by Step

$\bf{\text{Solution Outline:}}$ To find all $x$ such that $f(x) \lt0 ,$ with $f(x)= |8x-3| ,$ solve the inequality \begin{array}{l}\require{cancel} |8x-3|\lt0 .\end{array} $\bf{\text{Solution Details:}}$ The absolute value of $x,$ written as $|x|,$ is the distance of $x$ from $0.$ Since it is a distance, then $|x|$ is a nonnegative number. In the same way, the left side of the inequality, $|8x-3|\lt0,$ is always a nonnegative integer for any value of $n.$ This will never be less than the value at the right side. Hence, there is no solution.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.