Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 9 - Inequalities and Problem Solving - Review Exercises: Chapter 9 - Page 623: 27


$(-\infty, -3)\cup(-3,\infty)$

Work Step by Step

$\bf{\text{Solution Outline:}}$ The domain of the given function, $ f(x)=\dfrac{2x}{x+3} ,$ are all the values of $x$ for which the denominator is not $0.$ Express the answer in the interval notation. $\bf{\text{Solution Details:}}$ Since the denominator cannot be zero, then \begin{array}{l}\require{cancel} x+3\ne0 \\\\ x\ne-3 .\end{array} Hence, the domain is $ (-\infty, -3)\cup(-3,\infty) .$
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