Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 9 - Inequalities and Problem Solving - 9.3 Absolute-Value Equations and Inequalities - 9.3 Exercise Set: 10

Answer

Choice H

Work Step by Step

Since for any $c\gt0$, $|x|\lt c$ implies $-c\lt x\lt c$ (or $|x|\le c$ implies $-c\le x\le c$), the given inequality, $ |x-3|\lt5 ,$ is equivalent to \begin{array}{l}\require{cancel} -5\lt x-3\lt5 .\end{array} Hence, $\text{ Choice H .}$
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