## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Since for any $c\gt0$, $|x|\lt c$ implies $-c\lt x\lt c$ (or $|x|\le c$ implies $-c\le x\le c$), the given inequality, $|x-3|\lt5 ,$ is equivalent to \begin{array}{l}\require{cancel} -5\lt x-3\lt5 .\end{array} Hence, $\text{ Choice H .}$