## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson

# Chapter 9 - Inequalities and Problem Solving - 9.2 Intersections, Unions, and Compound Inequalities - 9.2 Exercise Set - Page 591: 91

#### Answer

$\left(-\infty, 4 \right]$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$ The domain of the given function, $f(x)=\sqrt{8-2x} ,$ is all values of $x$ for which the radicand is non-negative. Express the answer in interval notation. $\bf{\text{Solution Details:}}$ Since the radicand of a radical with an even index has to be non-negative, then \begin{array}{l}\require{cancel} 8-2x\ge0 \\\\ -2x\ge-8 .\end{array} Dividing both sides by a negative number (and consequently reversing the inequality symbol), the inequality above is equivalent to \begin{array}{l}\require{cancel} -2x\ge-8 \\\\ x\le\dfrac{-8}{-2} \\\\ x\le4 .\end{array} Hence the domain is $\left(-\infty, 4 \right]$

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