# Chapter 9 - Inequalities and Problem Solving - 9.2 Intersections, Unions, and Compound Inequalities - 9.2 Exercise Set - Page 591: 79

$(-\infty,6) \cup (6,\infty)$

#### Work Step by Step

$\bf{\text{Solution Outline:}}$ The domain of the given function, $f(x)=\dfrac{9}{x+6} ,$ is all values of $x$ for which the denominator is not $0.$ Express the answer in interval notation. $\bf{\text{Solution Details:}}$ Since the denominator of the given function cannot be $0$, then \begin{array}{l}\require{cancel} x+6\ne0 \\\\ x\ne-6 .\end{array} Hence the domain is $(-\infty,6) \cup (6,\infty) .$

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