## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Using "or," or the union of sets, the combined solutions of the given inequality \begin{array}{l}\require{cancel} \{x|x\le2\} \text{ }or\text{ } \{x|x\ge-2\} ,\end{array} is the graph consisting of all real numbers. Hence, $\text{ Choice I .}$