## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Using "and," or the intersection of sets, the common solutions of the given inequality \begin{array}{l}\require{cancel} \{x|x\le2\} \text{ }and\text{ } \{x|x\ge-2\} ,\end{array} is the graph consisting of all the points on and to the right of $-2$ and the points on and the left of $2.$ Hence, $\text{ Choice C .}$