Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 8 - Systems of Linear Equations and Problem Solving - Connecting: The Concepts - Exercises - Page 516: 7


The system has no solution

Work Step by Step

Equation 1 variable y isolated - select the substitution method. $y=\displaystyle \frac{5}{3}x+7\qquad $(*) Replace y with $\displaystyle \frac{5}{3}x+7$ in the second equation: $\displaystyle \frac{5}{3}x+7=\frac{5}{3}x-8\qquad$ ... and solve for $x$. ...add $-7-\displaystyle \frac{5}{3}x$ to both sides $ 0=-15\qquad$ ... a contradiction. The system has no solution (the graphs of the equations are parallel lines, no intersections.)
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