Answer
$(5,7)$
Work Step by Step
Equation 1 has variables isolated - select the substitution method.
$y=2x-3\qquad $(*)
Replace y with $2x-3$ in the second equation:
$ x+2x-3=12\qquad$ ... and solve for $x$. Simplify.
$ 3x-3=12\qquad$ ... add $3$ to both sides
$ 3x=15\qquad$ ... divide with 3
$x=5$
Now, back-substitute into (*)
$y=2(5)-3=10-3=7$
Form an ordered pair $(x,y) $ as the solution to the system
$(5,7)$
