Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 8 - Systems of Linear Equations and Problem Solving - 8.8 Business and Economics Applications - 8.8 Exercise Set - Page 563: 34

Answer

1

Work Step by Step

Solving the equation by factoring, we find: $$ 10x^2-20x+10 =0 \\ 10\left(x^2-2x+1\right) =0 \\ 10\left(x-1\right)^2 =0 \\ x=1$$
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