Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 8 - Systems of Linear Equations and Problem Solving - 8.3 Solving Applications: Systems of Two Equations - 8.3 Exercise Set - Page 527: 5

Answer

4 and 6

Work Step by Step

We first write the word problem as an equation. Next, we solve the equation using substitution. Doing this, we find: $$ x+y=10 \\ x=\frac{2}{3}y \\ \frac{2}{3}y+y=10\\ y=6 \\ x=\frac{2}{3}\cdot \:6 \\ x=4$$
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