Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 8 - Systems of Linear Equations and Problem Solving - 8.3 Solving Applications: Systems of Two Equations - 8.3 Exercise Set - Page 527: 12


31 two pointers and 9 three pointers.

Work Step by Step

We first write the word problem as an equation. Next, we solve the equation using substitution. Doing this, we find: $$ 2x+3y=89, x+y=40 \\ \frac{89-3y}{2}+y=40 \\ y=9 \\ x=\frac{89-3\cdot \:9}{2} \\ x=31$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.