## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$t_{1}=t_{2}-\displaystyle \frac{A}{vT}$
The goal is to isolate the wanted variable on one side of the equation. Multiply with $\displaystyle \frac{(t_{2}-t_{1})}{T}$ $T\times \displaystyle \frac{(t_{2}-t_{1})}{T}=\frac{A}{v(t_{2}-t_{1})}\times \displaystyle \frac{(t_{2}-t_{1})}{T}$ $t_{2}-t_{1}=\displaystyle \frac{A}{vT}\qquad$ ... subtract $t_{2}$ $-t_{1}=\displaystyle \frac{A}{vT}-t_{2}\qquad$ ... multiply with $-1$ $t_{1}=t_{2}-\displaystyle \frac{A}{vT}$