Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 7 - Functions and Graphs - Review Exercises: Chapter 7 - Page 497: 39

Answer

$r=\displaystyle \frac{2V-IR}{2I}$

Work Step by Step

The goal is to isolate the wanted variable on one side of the equation. First of all, the denominator must not be 0, $r\displaystyle \neq-\frac{R}{2}.$ Multiply both sides with $(R+2r)$ $I(R+2r)=2V$ $ IR+2Ir=2V\qquad$ ... subtract $IR$ $ 2Ir=2V-IR\qquad$ ... divide with $2I$ $r=\displaystyle \frac{2V-IR}{2I}$
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