#### Answer

$\color{blue}{(-\infty, -\frac{7}{3}) \cup (-\frac{7}{3}, 2) \cup (2, +\infty)}$

#### Work Step by Step

Find the domain of each function:
For $f(x)$, the value of $x$ cannot be $2$ since it will make the denominator zero. .
Thus, the domain of $f(x)$ is $(-\infty, 2) \cup (2, +\infty)$.
For $g(x)$, the value of $x$ can be any real number.
Thus, the domain of $g(x)$ is $(-\infty, +\infty)$.
RECALL:
The domain of the $(f/g)(x)$ is the common elements of the domains of $f(x)$ and $g(x)$ excluding $x$ values for which $g(x)=0$.
Note that when $g(-\frac{7}{3})=0$.
Thus, the domain of $(f/g)(x)$ is the set of all real numbers except $2$ and $-\frac{7}{3}$. In interval notation, the domain of $f/g$ is:
$\color{blue}{(-\infty, -\frac{7}{3}) \cup (-\frac{7}{3}, 2) \cup (2, +\infty)}$