Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 6 - Rational Expressions and Equations - Review Exercises: Chapter 6 - Page 437: 20

Answer

$$\frac{2x^2-2x}{x+1}$$

Work Step by Step

Recall, one never divides by a fraction. Rather, if we want to divide by a fraction, we multiply by the reciprocal of the fraction. Recall, the reciprocal of a fraction is that fraction with the numerator and the denominator switched. Thus, we find: $$ \frac{4x^4}{x^2-1}\times \frac{x^2-2x+1}{2x^3}\\ \frac{2x\left(x-1\right)^2}{\left(x+1\right)\left(x-1\right)}\\ \frac{2x\left(x-1\right)}{x+1}\\ \frac{2x^2-2x}{x+1}$$
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