Answer
$$\frac{7x+3}{x-3}$$
Work Step by Step
Recall, to simplify rational expressions, we look for common factors in the numerator and the denominator. Doing this, we find:
$$ \frac{14x^2-x-3}{2x^2-7x+3}\\ \frac{\left(7x+3\right)\left(2x-1\right)}{\left(2x-1\right)\left(x-3\right)}\\ \frac{7x+3}{x-3}$$
