Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 5 - Polynomials and Factoring - Connecting: The Concepts - Exercises: 9

Answer

$(n-9)(n-1)$

Work Step by Step

RECALL: A trinomial of the form $x^2+bx+c$ can be factored if there are integers $d$ and $e$ such that $c=de$ and $b=d+e$. The trinomial's factored form will be: $x^2+bx+c=(x+d)(x+e)$ The given trinomial has $b=-10$ and $c=9$. Note that $9=-9(-1)$ and $-10= -9+(-1)$. This means that $d=-9$ and $e=-1$ Thus, the factored form of the trinomial is: $[n+(-9)][n+(-1)] = (n-9)(n-1)$.
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