## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$6a^2-19a+10$
Distribute each term of the first factor to the second factor to obtain: $=3a(2a-5) -2(2a-5)$ Distribute $3a$ and $2$ to obtain: $=3a(2a)-3a(5) -2(2a)-2(-5) \\=6a^2-15a-4a-(-10) \\=6a^2-19a+10$