#### Answer

$6a^2-19a+10$

#### Work Step by Step

Distribute each term of the first factor to the second factor to obtain:
$=3a(2a-5) -2(2a-5)$
Distribute $3a$ and $2$ to obtain:
$=3a(2a)-3a(5) -2(2a)-2(-5)
\\=6a^2-15a-4a-(-10)
\\=6a^2-19a+10$

Published by
Pearson

ISBN 10:
0-32184-874-8

ISBN 13:
978-0-32184-874-1

$6a^2-19a+10$

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