## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\dfrac{x^{10}}{7^5}$
RECALL: (1) $\left(\frac{a}{b}\right)^m=\frac{a^m}{b^m}$ (2) $(a^m)^n=a^{mn}$ Use rule (1) above to obtain: $\left(\dfrac{x^2}{7}\right)^5=\dfrac{(x^2)^5}{7^5}$ Use rule (2) above to obtain: $=\dfrac{x^{2(5)}}{7^5} \\=\dfrac{x^{10}}{7^5}$