Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Study Summary - Practice Exercises: 6

Answer

$x^{30}y^{10}$

Work Step by Step

RECALL: (1) $(ab)^m=a^mb^m$ (2) $(a^m)^n=a^{mn}$ Use rule (1) above to obtain: $(x^3y)^{10}=(x^3)^{10}y^{10}$ Use rule (2) above to obtain: $=x^{3(10)}y^{10} \\=x^{30}y^{10}$
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