Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Review Exercises: Chapter 4 - Page 299: 54

Answer

$x^2-1.3x+0.40$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the product of 2 binomials, the product of the given expression, $ (x-0.8)(x-0.5) ,$ is \begin{array}{l}\require{cancel} x(x)+x(-0.5)-0.8(x)-0.8(-0.5) \\\\= x^2-0.5x-0.8x+0.40 \\\\= x^2-1.3x+0.40 .\end{array}
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