## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$x^2-1.3x+0.40$
Using $(a+b)(c+d)=ac+ad+bc+bd$ or the product of 2 binomials, the product of the given expression, $(x-0.8)(x-0.5) ,$ is \begin{array}{l}\require{cancel} x(x)+x(-0.5)-0.8(x)-0.8(-0.5) \\\\= x^2-0.5x-0.8x+0.40 \\\\= x^2-1.3x+0.40 .\end{array}