Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - Review Exercises: Chapter 4: 49

Answer

$a^2-3a-28$

Work Step by Step

Using $(a+b)(c+d)=ac+ad+bc+bd$ or the product of 2 binomials, the product of the given expression, $ (a-7)(a+4) ,$ is \begin{array}{l}\require{cancel} a(a)+a(4)-7(a)-7(4) \\\\= a^2+4a-7a-28 \\\\= a^2-3a-28 .\end{array}
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