Answer
$2a^5-3a^2$
Work Step by Step
Divide $8$ to each term to obtain:
$\dfrac{16a^5-24a^2}{8}=\dfrac{16a^5}{8}-\dfrac{24a^2}{8}=2a^5-3a^2$
Checking:
$8(2a^5-3a^2)=8(2a^5)-8(3a^2)=16a^5-24a^2$
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 4 - Polynomials - 4.8 Division of Polynomials - 4.8 Exercise Set - Page 290: 6
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