Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.8 Division of Polynomials - 4.8 Exercise Set - Page 290: 6



Work Step by Step

Divide $8$ to each term to obtain: $\dfrac{16a^5-24a^2}{8}=\dfrac{16a^5}{8}-\dfrac{24a^2}{8}=2a^5-3a^2$ Checking: $8(2a^5-3a^2)=8(2a^5)-8(3a^2)=16a^5-24a^2$
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