## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$8x^6-5x^3$
Divide $5$ to each term to obtain: $\dfrac{40x^6-25x^3}{5}=\dfrac{40x^6}{5}-\dfrac{25x^3}{5}=8x^6-5x^3$ Checking: $5(8x^6-5x^3)=5(8x^6)-5(5x^3)=40x^6-25x^3$