Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 3 - Introduction to Graphing - Mid-Chapter Review - Mixed Review: 20

Answer

x-intercept: $(-4, 0)$ y-intercept: $(0, 6)$

Work Step by Step

Find the x-intercept by setting $y=0$ then solving for $x$: $2y-3x=12 \\2(0)-3x=12 \\-3x=12 \\\frac{-3x}{-3}=\frac{12}{-3} \\x=-4$ Thus, the x-intercept is $(-4, 0)$. Find the y-intercept by setting $x=0$ then solving for $y$: $2y-3x=12 \\2y-3(0)=12 \\2y=12 \\\frac{2y}{2}=\frac{12}{2} \\y=6$ Thus, the y-intercept is $(0, 6)$.
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