## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$\approx 29.39\%$
Change in elevation: $14255-9600 = 4655$ ft Horizontal Distance: $15,840$ ft The average grade can be found by dividing the change in elevation by the horizontal distance, then converting the answer to percent: Average Grade $= \dfrac{4655\text{ ft}}{15840\text{ ft}}=\dfrac{931}{3168}=0.2938762626 \approx 29.39\%$