## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$y=-\dfrac{7}{2}x-7$
Using $y-y_1=\dfrac{y_1-y_2}{x_1-x_2}(x-x_1)$ or the Two-Point Form, then the equation of the line passing through the given points, $( -2,0 )\text{ and }( 0,-7 )$, is \begin{array}{l} y-0=\dfrac{0-(-7)}{-2-0}(x-(-2)) \\\\ y=\dfrac{0+7}{-2}(x+2) \\\\ y=-\dfrac{7}{2}(x+2) \\\\ y=-\dfrac{7}{2}x-7 .\end{array}