## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$y=2x+2$
Using $y-y_1=\dfrac{y_1-y_2}{x_1-x_2}(x-x_1)$ or the Two-Point Form, then the equation of the line passing through the given points, $( 3,8 )\text{ and }( 1,4 )$, is \begin{array}{l} y-8=\dfrac{8-4}{3-1}(x-3) \\\\ y-8=\dfrac{4}{2}(x-3) \\\\ y-8=2(x-3) \\\\ y-8=2x-6 \\\\ y=2x-6+8 \\\\ y=2x+2 .\end{array}