Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.2 Using the Principles Together - 2.2 Exercise Set: 98

Answer

$1$

Work Step by Step

Cancelling common factors between the numerator and the denominator,, then the given expression, $ \dfrac{2}{7}\cdot\dfrac{7}{2} $, simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{2}}{\cancel{7}}\cdot\dfrac{\cancel{7}}{\cancel{2}} \\\\= 1.\end{array}
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