## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$1$
Cancelling common factors between the numerator and the denominator,, then the given expression, $\dfrac{2}{7}\cdot\dfrac{7}{2}$, simplifies to \begin{array}{l}\require{cancel} \dfrac{\cancel{2}}{\cancel{7}}\cdot\dfrac{\cancel{7}}{\cancel{2}} \\\\= 1.\end{array}