Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 2 - Equations, Inequalities, and Problem Solving - 2.2 Using the Principles Together - 2.2 Exercise Set - Page 95: 97



Work Step by Step

Using the $LCD=18$, then the given expression, $ \dfrac{2}{9}+\dfrac{1}{6} $, simplifies to \begin{array}{l} \dfrac{2(2)+3(1)}{18} \\\\= \dfrac{4+3}{18} \\\\= \dfrac{7}{18} .\end{array}
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