Answer
True statement
Work Step by Step
$\sum\limits_{k=1}^{3}{{{k}^{2}}}$.
Use the summation of the sigma function,
$\sum\limits_{k=1}^{n}{{{a}^{k}}}={{a}^{1}}+{{a}^{2}}+{{a}^{3}}+\cdots +{{a}^{n-1}}+{{a}^{n}}$
The sigma function $\sum\limits_{k=1}^{3}{{{k}^{2}}}$ represents that the sum starts with ${{1}^{2}}$ and ends with ${{3}^{2}}$.
Thus, $\sum\limits_{k=1}^{3}{{{k}^{2}}}={{1}^{2}}+{{2}^{2}}+{{3}^{2}}$
Therefore, the given statement is true.
