Answer
$1120x^{12}y^2$
Work Step by Step
The $r+1$ th term in the binomial expansion of $(x+y)^n$ is:
$\binom{n}{r}x^{n-r}y^r$
Here $x=2x^3$, $y=\sqrt{y}$, $n=8$:
$r+1=5$
$r=4$
The indicated term is:
$\binom{8}{4}(2x^3)^{8-4}(\sqrt{y})^4=70\times2^4\times x^{12}\times y^2=1120x^{12}y^2$
