Answer
1275
Work Step by Step
$\binom{51}{49}=\frac{51!}{(51-49)!\times49!}=\frac{51!}{2!\times49!}=\frac{49!\times50\times51}{49!\times2!}=\frac{50\times51}{2!}=1275$
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 14 - Sequences, Series, and the Binomial Theorem - 14.4 The Binomial Theorem - 14.4 Exercise Set - Page 922: 24
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