Answer
$\frac{2t}{t-1}$
Work Step by Step
$\begin{align}
& \frac{t}{t-1}-\frac{t}{1-t}=\frac{t}{t-1}+\frac{t}{t-1} \\
& =\frac{t+t}{t-1} \\
& =\frac{2t}{t-1}
\end{align}$
Thus, $\frac{t}{t-1}-\frac{t}{1-t}$ reduces to $\frac{2t}{t-1}$.
Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)
by Bittinger, Marvin L.; Ellenbogen, David J.; Johnson, Barbara L.
Published by
Pearson
ISBN 10:
0-32184-874-8
ISBN 13:
978-0-32184-874-1
Chapter 14 - Sequences, Series, and the Binomial Theorem - 14.1 Sequences and Series - 14.1 Exercise Set - Page 895: 82
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