Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 14 - Sequences, Series, and the Binomial Theorem - 14.1 Sequences and Series - 14.1 Exercise Set - Page 895: 55



Work Step by Step

If we write out the sum, we get: $\sum_{k=1}^5\frac{1}{2k}=\frac{1}{2(1)}+\frac{1}{2(2)}+\frac{1}{2(3)}+\frac{1}{2(4)}+\frac{1}{2(5)}=\frac{1}{2}+\frac{1}{4}+\frac{1}{6}+\frac{1}{8}+\frac{1}{10}\approx1.141667$
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