Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 12 - Exponential Functions and Logarithmic Functions - 12.6 Solving Exponential Equations and Logarithmic Equations - 12.6 Exercise Set - Page 826: 68


Yes. Instead of applying $\quad \log_{e}e^{k}=k$, we apply $\quad \log_{10}e^{k}=k\cdot\log_{10}e$. (sample answer)

Work Step by Step

Taking the common logaritm on both sides, we would obtain $\log e^{0.06t}=\log 1500\qquad$ ... apply the power rule, $ 0.06t\log e==\log 1500\qquad$ ... divide with $(0.06\log e)$ $t=\displaystyle \frac{\log 1500}{0.06\log e}$ So, yes, we could have applied $\log$ instead of $\ln$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.