#### Answer

Yes.
Instead of applying $\quad \log_{e}e^{k}=k$,
we apply $\quad \log_{10}e^{k}=k\cdot\log_{10}e$.
(sample answer)

#### Work Step by Step

Taking the common logaritm on both sides, we would obtain
$\log e^{0.06t}=\log 1500\qquad$ ... apply the power rule,
$ 0.06t\log e==\log 1500\qquad$ ... divide with $(0.06\log e)$
$t=\displaystyle \frac{\log 1500}{0.06\log e}$
So, yes, we could have applied $\log$ instead of $\ln$.