Answer
Fill the blanks in this order:
$1,-2,-1$
$-2,-2,-1,1$
$2,8,2$
$2$
$2\sqrt{2},\ 2\sqrt{2}$
Work Step by Step
$ x^{2}-2x-1=0\qquad$... solve with the Quadratic formula.
$a=1,\ b=-2,\ c=-1$
$x=\displaystyle \frac{-(-2)\pm\sqrt{(-2)^{2}-4\cdot 1\cdot(-1)}}{2\cdot 1}$
$x=\displaystyle \frac{2\pm\sqrt{8}}{2}$
$x=\displaystyle \frac{2}{2}\pm\frac{2\sqrt{2}}{2}$
The solutions are $1+2\sqrt{2}$ and $1-2\sqrt{2.}$
