## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Fill the blanks in this order: $\pm\sqrt{5}$, $7\pm\sqrt{5}$, $\sqrt{5}$, $\sqrt{5}$.
$(x-7)^{2}=5\qquad$...use the principle of square roots. $x-7=\pm\sqrt{5}\qquad$...add $7$ to both sides. $x=7\pm\sqrt{5}$ The solutions are $7+\sqrt{5}$ and $7-\sqrt{5}$