Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.9 Polynomial Inequalities and Rational Inequalities - 11.9 Exercise Set - Page 765: 2

Answer

False statement

Work Step by Step

$\left( x+5 \right)\left( x-4 \right)\ge 0$ Now to find the intervals, set the inequality to 0. $\left( x+5 \right)\left( x-4 \right)=0$ The solution is, $\begin{align} & x+5=0 \\ & x=-5 \end{align}$ Or, $\begin{align} & x-4=0 \\ & x=4 \end{align}$ The roots divide the number line into three intervals: A, B and C. Now, check whether the inequality $\left( x+5 \right)\left( x-4 \right)\ge 0$ is satisfied or not. Take a test value from each interval and plug that into the equation as, For interval A, Test for $x=-6$ $\begin{align} & \left( -6+5 \right)\left( -6-4 \right)=\left( -1 \right)\left( -10 \right) \\ & =10\ge 0 \end{align}$ So, in the interval A, the inequality is satisfied. For interval B, Test for $x=0$ $\begin{align} & \left( 0+5 \right)\left( 0-4 \right)=\left( 5 \right)\left( -4 \right) \\ & =-20\not{\ge }0 \end{align}$ So, in the interval B, the inequality is not satisfied. For interval C, Test for $x=5$ $\begin{align} & \left( 5+5 \right)\left( 5-4 \right)=\left( 10 \right)\left( 1 \right) \\ & =10\ge 0 \end{align}$ So, in the interval C, the inequality is satisfied. So, from the above test, it is clear that the inequality $\left( x+5 \right)\left( x-4 \right)\ge 0$ is satisfied in the interval A: $\left( -\infty ,-5 \right)$ and B: $\left( 4,\infty \right)$ . The inequality symbol $\le $ means that the end points of the intervals is also included in the solution. Therefore, the solution of the inequality $\left( x+5 \right)\left( x-4 \right)\ge 0$ is $\left( -\infty ,-5 \right]\bigcup \left[ 4,\infty \right)$.
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