Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 11 - Quadratic Functions and Equations - 11.6 Quadratic Functions and Their Graphs - 11.6 Exercise Set - Page 740: 6

Answer

Please see image.
1565894888

Work Step by Step

The graph of $f(x)=ax^{2}$ is a parabola with $x=0$ as its axis of symmetry. Its vertex is the origin. For $a\gt 0$, the parabola opens upward. For $a\lt 0$, the parabola opens downward. If $|a|$ is greater than 1, the parabola is narrower than $y=x^{2}.$ If $|a|$ is between $0$ and 1, the parabola is wider than $y=x^{2}.$ The vertex of the graph of $f(x)=a(x-h)^{2}$ is $(h, 0)$ . --- $a=-1$, opens downward. The vertex is $(0,0)$. Make a table of function values and plot the points, and join with a smooth curve.
Small 1565894888
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.