Answer
Please see image.
Work Step by Step
The graph of $f(x)=a(x-h)^{2}$ has the same shape as the graph of $y=ax^{2}.$
If $h$ is positive, the graph is shifted $h$ units to the right.
If $h$ is negative, the graph is shifted $|h|$ units to the left.
For $a\gt 0$, the parabola opens upward.
For $a\lt 0$, the parabola opens downward.
If $|a|$ is greater than 1, the parabola is narrower than $y=x^{2}.$
If $|a|$ is between $0$ and 1, the parabola is wider than $y=x^{2}.$
The vertex is $(h, 0)$, and the axis of symmetry is $x=h.$
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$h=-5$; shifted $5$ units to the left, $a=-2$; opens downward.
The vertex is $(-5,0)$.
The axis of symmetry is $x=-5.$
Make a table of function values and plot the points,
and join with a smooth curve.
