Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Mid-Chapter Review - Mixed Review - Page 663: 20



Work Step by Step

Using the product of the sum and difference of like terms which is given by $(a+b)(a-b)=a^2-b^2,$ the given expression, $ (\sqrt{5}+3)(\sqrt{5}-3) ,$ is equivalent to \begin{array}{l}\require{cancel} (\sqrt{5}+3)(\sqrt{5}-3) \\\\= (\sqrt{5})^2-(3)^2 \\\\= 5-9 \\\\= -4 .\end{array}
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