Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 10 - Exponents and Radicals - Mid-Chapter Review - Mixed Review: 11

Answer

$y^{8}$

Work Step by Step

$\bf{\text{Solution Outline:}}$ Use the properties of radicals to simplify the given expression, $ \sqrt[3]{y^{24}} .$ $\bf{\text{Solution Details:}}$ Using the properties of radicals, the expression above simplifies to \begin{array}{l}\require{cancel} \sqrt[3]{y^{24}} \\\\= \sqrt[3]{(y^{8})^3} \\\\= y^{8} .\end{array}
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